延續上一篇文章
此程式為解碼用
BEGIN
s = NIL;
while not EOF
{
k = next input code;
entry = dictionary entry for k;
if (entry == NULL)
entry = s + s[0];
output entry;
if (s != NIL)
add string s + entry[0] to dictionary with a new code;
s = entry;
}
END
input = 1 4 4 2 7 3 3
s k entry/output code string
--------------------------------------
1 A
2 B
3 C
--------------------------------------
NIL 1 A
A 4 A 4 AA
A 4 AA 5 AA
AA 2 B 6 AAB
B 7 BB 7 BB
BB 3 C 8 BBC
C 3 C 9 CC
C eof
output = AAAABBBCC
#include <iostream>
#include <vector>
#include <string>
#include <fstream>
#include <sstream>
using namespace std;
int main( void )
{
vector<int> code; //向量code儲存碼
vector<string> str; //向量str儲存string
string input,s,entry;
char c;
int j,i=1,search_result,k;
stringstream input_num;
fstream file1,file2;
file1.open("input.txt"); //input為檔案資料輸入
file2.open("output.txt"); //output為檔案資料輸出
if(!file1 || !file2)
cout << "檔案開啟失敗";
//先將A B C 寫入字典
str.push_back("A");
code.push_back(1);
str.push_back("B");
code.push_back(2);
str.push_back("C");
code.push_back(3);
//解碼開始
while(1)
{
while(1) //讀取code 直到遇到空白停下
{
c = file1.get();
if( c == ' ' || file1.eof() )
break;
else
input = input + c;
}
input_num << input; //進行string轉成int的轉換
input_num >> k;
input_num.clear();
input.clear();
search_result = 0;
for(j=0;j<str.size();j++)
{
if( k == code[j] )
{
search_result = 1; //字典裡已有這個碼
entry = str[j];
break;
}
}
if( search_result == 0 ) //字典裡沒有這個碼
entry = s + s[0];
file2 << entry;
if( i != 1 )
{
str.push_back(s+entry[0]);
code.push_back(code.size()+1);
}
i=2;
s = entry;
if(file1.eof())
break;
}
//解碼結束
system("pause");
return 0;
}
2014年1月21日 星期二
LZW編碼(dictionary coding)
LZW編碼是資料壓縮的一種方法
以下是LZW的演算法及簡單實作出LZW編碼的程式
BEGIN
s = next input character;
while not EOF
{
c = next input character;
if s + c exists in the dictionary
s = s + c;
else
{
output the code for s;
add string s + c to the dictionary with a new code;
s = c;
}
}
output the code for s;
END
input = ABABBABCABABBA
s c output code string
--------------------------------
1 A
2 B
3 C
---------------------------------
A B 1 4 AB
B A 2 5 BA
A B
AB B 4 6 ABB
B A
BA B 5 7 BAB
B C 2 8 BC
C A 3 9 CA
A B
AB A 4 10 ABA
A B
AB B
ABB A 6 11 ABBA
A EOF 1
output = 1 2 4 5 2 3 4 6 1
#include <iostream>
#include <vector>
#include <string>
#include <fstream>
using namespace std;
int main( void )
{
vector<int> code; //向量code儲存碼
vector<string> str; //向量str儲存string
string input,s,c,temp;
int j,i=1,search_result;
fstream file1,file2;
file1.open("input.txt"); //input為檔案資料輸入
file2.open("output.txt"); //output為檔案資料輸出
if(!file1 || !file2)
cout << "檔案開啟失敗";
else
file1 >> input; //讀進檔案裡的資料後 寫入input
//先將A B C 寫入字典
str.push_back("A");
code.push_back(1);
str.push_back("B");
code.push_back(2);
str.push_back("C");
code.push_back(3);
//編碼開始
s = input[0];
while(1)
{
c = input[i++];
temp = s + c;
for(j=0;j<str.size();j++)
{
if(temp == str[j]) //temp已在字典裡
{
s = s + c;
search_result = 1;
break;
}
search_result = 0; //temp不再字典裡
}
if( search_result == 0 )
{
for(j=0;j<str.size();j++)
{
if( s == str[j] )
{
file2 << code[j] << " ";
break;
}
}
str.push_back(temp);
code.push_back(code.size()+1);
s = c;
}
if( i == input.size() )
break;
}
for(j=0;j<str.size();j++)
{
if( s == str[j] )
file2 << code[j];
}
//編碼結束
system("pause");
return 0;
}
以下是LZW的演算法及簡單實作出LZW編碼的程式
BEGIN
s = next input character;
while not EOF
{
c = next input character;
if s + c exists in the dictionary
s = s + c;
else
{
output the code for s;
add string s + c to the dictionary with a new code;
s = c;
}
}
output the code for s;
END
input = ABABBABCABABBA
s c output code string
--------------------------------
1 A
2 B
3 C
---------------------------------
A B 1 4 AB
B A 2 5 BA
A B
AB B 4 6 ABB
B A
BA B 5 7 BAB
B C 2 8 BC
C A 3 9 CA
A B
AB A 4 10 ABA
A B
AB B
ABB A 6 11 ABBA
A EOF 1
output = 1 2 4 5 2 3 4 6 1
#include <iostream>
#include <vector>
#include <string>
#include <fstream>
using namespace std;
int main( void )
{
vector<int> code; //向量code儲存碼
vector<string> str; //向量str儲存string
string input,s,c,temp;
int j,i=1,search_result;
fstream file1,file2;
file1.open("input.txt"); //input為檔案資料輸入
file2.open("output.txt"); //output為檔案資料輸出
if(!file1 || !file2)
cout << "檔案開啟失敗";
else
file1 >> input; //讀進檔案裡的資料後 寫入input
//先將A B C 寫入字典
str.push_back("A");
code.push_back(1);
str.push_back("B");
code.push_back(2);
str.push_back("C");
code.push_back(3);
//編碼開始
s = input[0];
while(1)
{
c = input[i++];
temp = s + c;
for(j=0;j<str.size();j++)
{
if(temp == str[j]) //temp已在字典裡
{
s = s + c;
search_result = 1;
break;
}
search_result = 0; //temp不再字典裡
}
if( search_result == 0 )
{
for(j=0;j<str.size();j++)
{
if( s == str[j] )
{
file2 << code[j] << " ";
break;
}
}
str.push_back(temp);
code.push_back(code.size()+1);
s = c;
}
if( i == input.size() )
break;
}
for(j=0;j<str.size();j++)
{
if( s == str[j] )
file2 << code[j];
}
//編碼結束
system("pause");
return 0;
}
RGB_YUV_Extraction
將一張大小為512*512的RAW檔裡的RGB值及YUV值抽取出來各成為一張圖片
其中RAW檔裡資料的排列方式為藍、綠、紅、藍、綠、紅....
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#include<cmath>
其中RAW檔裡資料的排列方式為藍、綠、紅、藍、綠、紅....
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#include<cmath>
int main()
{
int i;
FILE *orimage=fopen("desert.raw", "rb"); //輸入檔為一張RAW檔
unsigned char buffer[786432]; //512*512*3
{
int i;
FILE *orimage=fopen("desert.raw", "rb"); //輸入檔為一張RAW檔
unsigned char buffer[786432]; //512*512*3
FILE *blue=fopen("desertRed.raw", "wb");
FILE *green=fopen("desertGreen.raw", "wb");
FILE *red=fopen("desertBlue.raw", "wb");
FILE *y=fopen("deserty.raw","wb");
FILE *u=fopen("desertu.raw","wb");
FILE *v=fopen("desertv.raw","wb");
for( i=0; i<786432; i++)
{
buffer[i] = getc(orimage); //依次讀一個 byte , 三個一組 , 依序存入紅綠藍 三檔案裡
if( (i%3) == 0)
putc(buffer[i],blue);
if( (i%3) == 1)
putc(buffer[i],green);
if( (i%3) == 2)
{
putc(buffer[i],red);
putc( (buffer[i-2]*0.114 + buffer[i-1]*0.587 + buffer[i]*0.299),y); //進行YUV矩陣換算
putc( fabs(buffer[i-2]*0.437 + buffer[i-1]*(-0.289) + buffer[i]*(-0.148)),u);
putc( fabs(buffer[i-2]*(-0.100) + buffer[i-1]*(-0.515) + buffer[i]*0.615),v);
}
}
system("pause");
return 0;
}
FILE *green=fopen("desertGreen.raw", "wb");
FILE *red=fopen("desertBlue.raw", "wb");
FILE *y=fopen("deserty.raw","wb");
FILE *u=fopen("desertu.raw","wb");
FILE *v=fopen("desertv.raw","wb");
for( i=0; i<786432; i++)
{
buffer[i] = getc(orimage); //依次讀一個 byte , 三個一組 , 依序存入紅綠藍 三檔案裡
if( (i%3) == 0)
putc(buffer[i],blue);
if( (i%3) == 1)
putc(buffer[i],green);
if( (i%3) == 2)
{
putc(buffer[i],red);
putc( (buffer[i-2]*0.114 + buffer[i-1]*0.587 + buffer[i]*0.299),y); //進行YUV矩陣換算
putc( fabs(buffer[i-2]*0.437 + buffer[i-1]*(-0.289) + buffer[i]*(-0.148)),u);
putc( fabs(buffer[i-2]*(-0.100) + buffer[i-1]*(-0.515) + buffer[i]*0.615),v);
}
}
system("pause");
return 0;
}
Divide-and-Conquer for Maxima Finding
演算法:
定義: P1(x1,y1) dominate P2(x2,y2) if only if x1 >= x2 and y1 >= y2
A point is called a max point if no other point dominate it
輸入:一些平面上的點
輸出:THE MAXIMAL points
1. if 只有一點, 回傳它就是 max point
不然找一直線L垂直X軸 並且分割S成一半 SL and SR
2. 持續遞迴直到剩下兩點或一點, 進行比較
3. 開始merge, 在SR裡找到一點有最大的Y值,記錄它,
並且在SL裡判斷所有的點的Y值有沒有小於這點的Y,
如果有,刪除這點
程式碼實作如下
#include <stdio.h>
#include <stdlib.h>
struct vertex //座標資料
{
int x; //紀錄X位置
int y; //紀錄Y位置
int max_point; //紀錄是否為max_point
};
void per( struct vertex *vertex_arr1, int init, int end) //per函式將所有點一分為二 init為初始注標 end為結尾注標
{
int i,maxy=0,maxx=0;
if( init == end ) //if分割到只勝一點 將這點指派為max_point
vertex_arr1[init].max_point = 1;
else
{
per(vertex_arr1, init, (init + end )/2); //分割後 前半段帶入遞迴
//開始merge
for(i=(init + end )/2+1;i<=end;i++) // 找後半段的最大y值的點
{
if( maxy < vertex_arr1[i].y )
{
maxx = vertex_arr1[i].x;
maxy = vertex_arr1[i].y;
}
}
for(i=init;i<=(init + end)/2;i++) // 前半段的點若為max_point 則判斷此點x y值 若小於maxx maxy 則為不合的點
{
if( vertex_arr1[i].max_point == 1 && vertex_arr1[i].x < maxx && vertex_arr1[i].y < maxy )
vertex_arr1[i].max_point = 0;
}
per(vertex_arr1, (init + end )/2+1, end); //分割後 後半段帶入遞迴
}
}
int main(void)
{
int i,max=0,j,temp;
char c[10];
FILE *fp;
fp = fopen("input.txt","r+");
i=0;
while(1) //讀檔
{
i++;
if( fgets(c,10,fp) == NULL )
break;
}
max = i-1; // 算有幾個點
fseek(fp,0L,SEEK_SET); //移回檔頭
struct vertex *vertex_arr = malloc( max * sizeof(struct vertex) );
for(i=0;i<max;i++) //初始化
{
vertex_arr[i].x = -1;
vertex_arr[i].y = -1;
vertex_arr[i].max_point = 0;
}
i=0;
while(1) //讀檔 並放入vertex 結構
{
fscanf( fp,"%d,%d",&(vertex_arr[i].x) ,&(vertex_arr[i].y) );
i++;
if( getc(fp) == EOF )
break;
}
//先按照X值由小到大排列
for(i=0;i<max;i++)
{
for(j=i+1;j<max;j++)
{
if( vertex_arr[i].x > vertex_arr[j].x )
{
temp = vertex_arr[i].x;
vertex_arr[i].x = vertex_arr[j].x;
vertex_arr[j].x = temp;
temp = vertex_arr[i].y;
vertex_arr[i].y = vertex_arr[j].y;
vertex_arr[j].y = temp;
}
}
}
per(vertex_arr,0,max-1); //開始遞迴
for(i=0;i<max;i++) //印出max_point
{
if( vertex_arr[i].max_point == 1 )
printf("%d,%d\n",vertex_arr[i].x ,vertex_arr[i].y);
}
system("pause");
return 0;
}
輸入請以讀入檔案方式。
例如:以下檔案內容,代表5個平面座標點
2,3
4,5
6,7
8,9
10,11
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